1)3240:6=540
2) 540:54=10 glyukoza anaerob
3)540x18=9720 9720–60%
X – 100%
X=16200 Xp ATF miqdori
4) 16200: 30 = 540 Mx ATF
5) 540:36=15 glyukoza aerob
6) 10+15=25 25– 50%
X – 100%
X=50 mol glyukoza
Nazorat: Biologiya 9-sinf BSB ¹5 DEMO variant
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